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Introduction to Derivatives

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It is all about slope!
Slope = Change in YChange in X
gradient

We can find an average slope between two points.

average slope = 24/15
But how do we find the slope at a point?
There is nothing to measure!
slope 0/0 = ????
But with derivatives we use a small difference ...
... then have it shrink towards zero.
slope delta y / delta x

Let us Find a Derivative!

To find the derivative of a function y = f(x) we use the slope formula:
Slope = Change in YChange in X = Î”yΔx
slope delta x and delta y
And (from diagram) we see that:
x changes fromxtox+Δx
y changes fromf(x)tof(x+Δx)
Now follow these steps:
  • Fill in this slope formula: Î”yΔx = f(x+Δx) − f(x)Δx
  • Simplify it as best we can
  • Then make Î”x shrink towards zero.
Like this:

Example: the function f(x) = x2

We know f(x) = x2, and can calculate f(x+Δx:
Start with:f(x+Δx) = (x+Δx)2
Expand (x + Δx)2:f(x+Δx) = x2 + 2x Δx + (Δx)2

The slope formula is:f(x+Δx) − f(x)Δx
Put in f(x+Δx) and f(x):x2 + 2x Δx + (Δx)2 − x2Δx
Simplify (x2 and −x2 cancel):2x Δx + (Δx)2Δx
Simplify more (divide through by Î”x):  = 2x + Δx
And then as Δx heads towards 0 we get:= 2x

Result: the derivative of x2 is 2x

We write dx instead of "Δx heads towards 0", so "the derivative of" is commonly written d/dx
d/dxx2 = 2x
"The derivative of x2 equals 2x"
or simply "d dx of x2 equals 2x"
slope x^2 at 2 is 4

What does d/dxx2 = 2x mean?

It means that, for the function x2, the slope or "rate of change" at any point is 2x.
So when x=2 the slope is 2x = 4, as shown here:
Or when x=5 the slope is 2x = 10, and so on.
Note: sometimes f’(x) is also used for "the derivative of":
f’(x) = 2x
"The derivative of f(x) equals 2x"
or simply "f-dash of x equals 2x"

Let's try another example.

Example: What is d/dxx3 ?

We know f(x) = x3, and can calculate f(x+Δx:
Start with:f(x+Δx) = (x+Δx)3
Expand (x + Δx)3:f(x+Δx) = x3 + 3x2 Î”x + 3x (Δx)2 + (Δx)3

The slope formula:f(x+Δx) − f(x)Δx
Put in f(x+Δx) and f(x):x3 + 3x2 Î”x + 3x (Δx)2 + (Δx)3 − x3Δx
Simplify (x3 and −x3 cancel):3x2 Î”x + 3x (Δx)2 + (Δx)3Δx
Simplify more (divide through by Î”x):  = 3x2 + 3x Δx + (Δx)2
And then as Δx heads towards 0 we get:d/dxx3 = 3x2
Have a play with it using the Derivative Plotter.

Derivatives of Other Functions

We can use the same method to work out derivatives of other functions (like sine, cosine, logarithms, etc).
But in practice the usual way to find derivatives is to use:

Example: what is the derivative of sin(x) ?

On Derivative Rules it is listed as being cos(x)
Done.
Using the rules can be tricky!

Example: what is the derivative of cos(x)sin(x) ?

You can't just find the derivative of cos(x) and multiply it by the derivative of sin(x) ... you must use the "Product Rule" as explained on the Derivative Rules page.
It actually works out to be cos2(x) - sin2(x)
So that is your next step: learn how to use the rules.

Notation

"Shrink towards zero" is actually written as a limit like this:
f-dash of x equals lim as delta x goes to 0 of ( f(x + delta x) - f(x) ) / delta x
"The derivative of f equals the limit as Î”x goes to zero of f(x+Δx) - f(x) over Î”x

Or sometimes the derivative is written like this (explained on Derivatives as dy/dx):
dy/dx ( f(x + dx) - f(x) ) / dx

The process of finding a derivative is called "differentiation".
You do differentiation ... to get a derivative.

Where to Next?

Go and learn how to find derivatives using Derivative Rules, and get plenty of practice.

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